Sunpal Custom 3000W/5000W Off-Grid Solar Energy System for Sale

Product Features

  • Sunpal photovoltaic power kit 3000W 5000W
  • Sunpal 3000W 5000W solar panel kit
  • Sunpal 3000W 5000W off grid solar power kit Supplier
  • Sunpal 3000W 5000W solar energy system
  • Sunpal photovoltaic power kit 3000W 5000W
  • Sunpal 3000W 5000W solar panel kit
  • Sunpal 3000W 5000W off grid solar power kit Supplier
  • Sunpal 3000W 5000W solar energy system

Sunpal Custom 3000W/5000W Off-Grid Solar Energy System for Sale

Product Features

    Mono PERC or TOPCon solar panels
    MPPT controller with timing control
    Lithium or lead-acid battery optional
    WiFi and GPRS remote monitoring
    Built-in dust-proof protection
    Custom inverter and mounting options

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ComponentsSP1KW-OFFSP2KW-OFFSP3KW-OFFSP4KW-OFFSP5KW-OFF
340W Mono Solar Panel2 Piece4 Piece6 Piece9 Piece12 Piece
MC4 Y Branch1 Pair1 Pair2 Pair//
Combiner Box///3 in 1 out4 in 1 out
Off Grid Inverter1KW2KW3KW4KW5KW
12V 200AH Battery1 Piece2 Piece4 Piece4 Piece8 Piece
DC Cable100 Meters100 Meters200 Meters200 Meters200 Meters
MC4 Connector4 Pair4 Pair6 Pair6 Pair8 Pair
Mounting SystemStandards Pitched Roof ( Customized Optional)
Sunpal Hybrid Solar Power System 6kW 8kW With Panels
Sunpal Photovoltaic Solar System 6kW 8kW Hybrid

Q :

1. What type of solar panel does this system use?

A :

It includes high-efficiency monocrystalline silicon solar panels, ideal for residential off-grid setups.

Q :

2. Can this system work with both lithium and lead-acid batteries?

A :

Yes, it supports both lithium-ion and lead-acid batteries depending on your storage preference.

Q :

3. Is remote monitoring available?

A :

Yes, WiFi and GPRS remote monitoring options are available for real-time performance tracking.

Q :

4. Can I use this system with a backup generator?

A :

Absolutely. It's compatible with both mains voltage and generator power input.

Q :

5. Is this system suitable for rooftop or ground installation?

A :

Yes, it supports both ground mounting and pitched rooftop configurations with customizable mounting kits.

Q :

6. For a monthly consumption of 300 kWh, what size solar system is needed?

A :

To meet a monthly electricity demand of 300 kWh, a DC solar panel array with a capacity between 2.7 kW and 3.2 kW is typically required (assuming 4-5 hours of peak sunlight per day and a system loss rate of 15%-25%). New Jersey's local guideline, each installed kilowatt of solar capacity generates approximately 1,200 kWh annually. Therefore, to meet an annual electricity demand of 3,600 kWh, a system of roughly 3 kW is needed.

1. Detailed Capacity Calculation Method (also applicable for B2B/large systems)

300 kWh ÷ 30 days = 10 kWh/day

2. Estimate Peak Sun Hours (PSH) for Your Location

This value represents the number of hours per day that solar panels operate at their full rated power output. In the United States, typical values range from 3 to 6 PSH depending on geographic location. Most areas in New Jersey average around 4.5 PSH. Specific values can be obtained using solar irradiance maps or tools such as NSRDB or PVWatts.

3. Account for system losses/derating

No system achieves 100% efficiency. Typical losses include:

Inverter conversion losses
Cable (DC/AC) losses
Module mismatch/degradation
Temperature/thermal losses
Effects of soiling, shading, dust
Inverter clipping or shutdown
Actual derating factors should range between 0.75 and 0.85 (representing 15–25% losses). Prioritize installer estimates if available.

4. Calculate Required DC Array Capacity

Required DC size (kW) = Daily kWh demand ÷ (PSH × derating factor)

Example:

Storage duration = 5 hours, derating factor = 0.80 → Required capacity = 10 ÷ (5 × 0.80) = 2.5 kW
Storage duration = 4 hours, derating factor = 0.80 → Required power = 10 ÷ (4 × 0.80) = 3.125 kW
In practical applications, intermediate values are typically used, such as ~2.7–3.2 kW.

5. Verify Using Local Empirical Rules

In New Jersey, a 1 kW solar system generates approximately 1,200 kWh annually.

Annual electricity consumption = 300 × 12 = 3,600 kWh
Required power = 3,600 ÷ 1,200 = 3.0 kW
This result aligns with the above estimate after accounting for losses.

6. B2B/Large-Scale System Optimization Approach

DC/AC Capacity Ratio/Over-Design Factor: Set DC module capacity to 1.1–1.3 times AC inverter capacity to boost generation under low irradiance, though this may cause power curtailment during peak periods.

Seasonal Fluctuations/Buffer Capacity Design: Add 10–20% redundant capacity if high electricity demand occurs during low-sunlight months (winter).

Inverter Efficiency and Clipping Losses: Inverter efficiency may fall below 100% under specific loads. When module output exceeds inverter ratings, overcapacity leads to power clipping.

Physical Constraints/Shading/Orientation: If portions of the roof are shaded or poorly oriented, increase capacity or optimize layout.

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